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Stage 5 · Algebra

10 problems · AIME late · mathsolympiadprep.com

The answer key prints on its own page at the end.

  1. Find all solutions to the equation 2017x2016x=12017^{x}-2016^{x}=1.

    Translate the above text into English, please keep the original text's line breaks and format, and output the translation result directly.

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  2. Given tt is a real number. Find all functions f:RRf: \mathbf{R} \rightarrow \mathbf{R} such that
    f(x+t+f(y))=f(f(x))+f(t)+y. f(x+t+f(y))=f(f(x))+f(t)+y .
    (2014, Croatian Mathematical Olympiad)

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  3. Let akπ2(k=0,±1,±2,),Tsina+tanacosa+cotaa \neq \frac{k \pi}{2}(k=0, \pm 1, \pm 2, \cdots), T \equiv \frac{\sin a+\tan a}{\cos a+\cot a}.

    1. ATT takes negative values
    2. BTT takes non-negative values
    3. CTT takes positive values
    4. DTT can take both positive and negative values

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  4. 131613 \cdot 16 If 0<x<10<x<1, then among x2,x,x,1xx^{2}, x, \sqrt{x}, \frac{1}{x}
    (A) 1x\frac{1}{x} is the largest, x2x^{2} is the smallest.
    (B) xx is the largest, 1x\frac{1}{x} is the smallest.
    (C) x2x^{2} is the largest, x\sqrt{x} is the smallest.
    (D) xx is the largest, x2x^{2} is the smallest.
    (China Junior High School Mathematics Correspondence Competition, 1987)

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  5. Let the function y=tanωx(ω>0)y=\tan \omega x(\omega>0) intersect the line y=ay=a at points AA and BB, and the minimum value of AB|A B| is π\pi. Then the monotonic increasing interval of the function
    f(x)=3sinωxcosωx f(x)=\sqrt{3} \sin \omega x-\cos \omega x
    is:

    1. A[2kππ6,2kπ+π6](kZ)\left[2 k \pi-\frac{\pi}{6}, 2 k \pi+\frac{\pi}{6}\right](k \in \mathbf{Z})
    2. B[2kππ3,2kπ+2π3](kZ)\left[2 k \pi-\frac{\pi}{3}, 2 k \pi+\frac{2 \pi}{3}\right](k \in \mathbf{Z})
    3. C[2kπ2π3,2kπ+π3](kZ)\left[2 k \pi-\frac{2 \pi}{3}, 2 k \pi+\frac{\pi}{3}\right](k \in \mathbf{Z})
    4. D[2kππ6,2kπ+5π6](kZ)\left[2 k \pi-\frac{\pi}{6}, 2 k \pi+\frac{5 \pi}{6}\right](k \in \mathbf{Z})

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  6. The dimensions of a television screen are 60 cm×45 cm60~\mathrm{cm} \times 45~\mathrm{cm}. A camera films the entire television, and sends the image back onto the television itself, so that inside this television another one can be seen, and so on. The largest television seen inside the screen has an area equal to half the area of the screen. Assuming that a person watches the television seated at a distance such that they cannot distinguish images with an area smaller than 1 cm21~\mathrm{cm}^2, how many televisions does he see inside the screen?

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  7. Let g1(x)=13(1+x+x2+)g_{1}(x)=\frac{1}{3}\left(1+x+x^{2}+\cdots\right) for all values of xx for which the right hand side converges. Let gn(x)=g1(gn1(x))g_{n}(x)=g_{1}\left(g_{n-1}(x)\right) for all integers n2n \geq 2. What is the largest integer rr such that gr(x)g_{r}(x) is defined for some real number xx ?

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  8. If a+log32017,a+log92017,a+log272017(aR)a+\log _{3} 2017, a+\log _{9} 2017, a+\log _{27} 2017(a \in R) form a geometric sequence, then its common ratio is \qquad

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  9. Let x,y,zx, y, z be the roots of the equation t32t29t1=0t^{3}-2 t^{2}-9 t-1=0. Find yzx+xzy+xyz\frac{y z}{x}+\frac{x z}{y}+\frac{x y}{z}.

    (12 points)

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  10. (5 points)
    Xiyangyang, Meiyangyang, and Nuanyangyang went treasure hunting, and each of them found some gold coins. Xiyangyang's number of gold coins is 14\frac{1}{4} of the total number of gold coins the other two have, Meiyangyang's number of gold coins is 13\frac{1}{3} of the total number of gold coins the other two have, and Nuanyangyang has 176 gold coins. Therefore, the total number of gold coins they found is \qquad.

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Answer key — Stage 5 · Algebra

Worked solutions for every problem are on the site, one page per problem.

  1. 11 open
  2. f(x)=xf(x)=x open
  3. CC open
  4. AA open
  5. [2kππ3,2kπ+2π3](kZ)[2k\pi-\frac{\pi}{3},2k\pi+\frac{2\pi}{3}](k\in{Z}) open
  6. 1111 open
  7. 55 open
  8. 13\frac{1}{3} open
  9. 7777 open
  10. 320320 open

Problems belong to the competitions that set them and are reproduced from open datasets under their licences; every problem page names its source. Free to copy for classroom use.