Problem 161

To solve each of the given problems step by step, we follow the given solutions closely, breaking down the calculations in a detailed manner.

### Problem 1:
Calculate $-2.4 + 3.5 - 4.6 + 3.5$.

We start by grouping the positive and negative numbers:
$$\begin{align*} -2.4 + 3.5 - 4.6 + 3.5 &= (-2.4 - 4.6) + (3.5 + 3.5) \\ &= -7 + 7 \\ &= 0. \end{align*}$$
Thus, the answer is $\boxed{0}$.

### Problem 2:
Calculate $(-40) - (-28) - (-19) + (-24)$.

We simplify the expression by changing the double negatives to positives:
$$\begin{align*} (-40) - (-28) - (-19) + (-24) &= (-40) + 28 + 19 + (-24) \\ &= -17. \end{align*}$$
So, the answer is $\boxed{-17}$.

### Problem 3:
Calculate $(-3) \times \frac{5}{6} \times (-\frac{4}{5}) \times (-\frac{1}{4})$.

We multiply the fractions step by step:
$$\begin{align*} -3 \times \frac{5}{6} \times \frac{4}{5} \times \frac{1}{4} &= -\frac{1}{2}. \end{align*}$$
Therefore, the answer is $\boxed{-\frac{1}{2}}$.

### Problem 4:
Calculate $(-\frac{5}{7}) \times (-\frac{4}{3}) ÷ (-2\frac{1}{7})$.

First, we convert the mixed number to an improper fraction:
$$-2\frac{1}{7} = -\frac{15}{7}.$$

Then, we perform the multiplication and division:
$$\begin{align*} -\frac{5}{7} \times \frac{4}{3} \times \frac{7}{15} &= -\frac{4}{9}. \end{align*}$$
Hence, the final answer is $\boxed{-\frac{4}{9}}$.