A six-digit number starts with one. If this one is moved to the end of the number, the resulting number will be three times the given number. Find the given number.
(7-10 grades)
A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.
33.1. The desired six-digit number has the form 1abcde. According to the problem, 3⋅1abcde=abcde1 or 3(100000+abcde)=1+10⋅abcde. From this, 7⋅abcde=299999, i.e., abcde=42857. Therefore, the desired number is 142857.
Source: NuminaMath-1.5,
licensed Apache-2.0.
Statement reproduced verbatim; metadata (topic, difficulty, ordering) added by this project.