Maths Olympiad Prep

Track / Stage 3 / 155 of 260 #155 of 1964

Problem 155

AMC 10/12, early questions
Geometry Difficulty 3.5 Multiple choice

Line segment AB\overline{AB} is a diameter of a circle with AB=24AB = 24. Point CC, not equal to AA or BB, lies on the circle. As point CC moves around the circle, the centroid (center of mass) of ABC\triangle ABC traces out a closed curve missing two points. To the nearest positive integer, what is the area of the region bounded by this curve?

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Official solution

For each ABC,\triangle ABC, note that the length of one median is OC=12.OC=12. Let GG be the centroid of ABC.\triangle ABC. It follows that OG=13OC=4.OG=\frac13 OC=4.
As shown below, ABC1\triangle ABC_1 and ABC2\triangle ABC_2 are two shapes of ABC\triangle ABC with centroids G1G_1 and G2,G_2, respectively:

Therefore, point GG traces out a circle (missing two points) with the center OO and the radius OG,\overline{OG}, as indicated in red. To the nearest positive integer, the area of the region bounded by the red curve is πOG2=16π(C) 50.\pi\cdot OG^2=16\pi\approx\boxed{\textbf{(C) } 50}.
~MRENTHUSIASM

Source: NuminaMath-1.5, licensed Apache-2.0. Statement reproduced verbatim; metadata (topic, difficulty, ordering) added by this project.