A line is drawn through the centroid of triangle , intersecting sides and . We will prove that the sum of the distances from points and to the line is equal to the distance from point to this line.
Given (Fig. 37): - centroid of , .
To Prove: .
A line is drawn through the centroid of triangle , intersecting sides and . We will prove that the sum of the distances from points and to the line is equal to the distance from point to this line.
Given (Fig. 37): - centroid of , .
To Prove: .
Proof. Let's consider a purely geometric proof.
Draw the median of triangle . Since point is the centroid of , then . Drop a perpendicular from point to line . Since and , then , i.e., quadrilateral is either a rectangle (if ) or a trapezoid (if ).
If , then from the similarity of triangles and it follows that . Since in the considered case , then .
If , then since and , then is the midline of trapezoid , i.e.,
Since , , and , then and therefore
hence,
Comparing the expressions for from equations (33.1) and (33.2), we get: