Track / Stage 4 / 22 of 340 #282 of 1964

Problem 282

AMC 12 late, AIME early

Algebra Difficulty 4.4 Multiple choice

If $x+y+z=25$ and $y+z=14$ , then $x$ is

Pick one

Official solution

If $x+y+z=25$ and $y+z=14$ , then $x$ is
(A) 8
(B) 11
(C) 6
(D) -6
(E) 31

## Solution

We are given that $x+y+z=25$

$\text { and } \quad y+z=14$

Subtract equation (2) from equation (1) to get $x=11$ .

ANSWER: (B)

## PART B:

Source: NuminaMath-1.5, licensed Apache-2.0. Statement reproduced verbatim; metadata (topic, difficulty, ordering) added by this project.