Maths Olympiad Prep

Track / Stage 3 / 77 of 260 #77 of 1964

Problem 77

AMC 10/12, early questions
Combinatorics Difficulty 3.2 Multiple choice

Rabbits Peter and Pauline have three offspring—Flopsie, Mopsie, and Cotton-tail. These five rabbits are to be distributed to four different pet stores so that no store gets both a parent and a child. It is not required that every store gets a rabbit. In how many different ways can this be done?

Pick one

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Official solution

There are two possibilities regarding the parents.
1) Both are in the same store. In this case, we can treat them both as a single bunny, and they can go in any of the 4 stores. The 3 baby bunnies can go in any of the remaining 3 stores. There are 433=1084 \cdot 3^3 = 108 combinations.

2) The two are in different stores. In this case, one can go in any of the 4 stores, and the other can go in any of the 3 remaining stores. The 3 baby bunnies can each go in any of the remaining 2 stores. There are 4323=964 \cdot 3 \cdot 2^3 = 96 combinations.
Adding up, we get 108+96=204108 + 96 = 204 combinations.

Source: NuminaMath-1.5, licensed Apache-2.0. Statement reproduced verbatim; metadata (topic, difficulty, ordering) added by this project.