Solution: Since △DEC is an equilateral triangle, then ∣DE∣=∣CE∣ each angle has a measure of 60∘. This implies that ∠ADE has measure of 30∘. Since ∣AD∣=∣DE∣, then △ADE is an isosceles triangle. Thus, ∠DAE=∠DEA=75∘. The same argument on triangle BEC will give us ∠CBE=∠CEB=75∘. Thus, ∠AEB=150∘.
Source: NuminaMath-1.5,
licensed Apache-2.0.
Statement reproduced verbatim; metadata (topic, difficulty, ordering) added by this project.