Maths Olympiad Prep

Track / Stage 3 / 105 of 260 #105 of 1964

Problem 105

AMC 10/12, early questions
Algebra Difficulty 3.2 Multiple choice

Given that mm is a real constant, proposition pp: ∀x∈R\forall x \in \mathbb{R}, x2−4x+2m≥0x^2 - 4x + 2m \geq 0, then "m≥3m \geq 3" is the ("blank") for "proposition pp is true".

Pick one

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Official solution

When proposition pp is true, ∀x∈R\forall x \in \mathbb{R}, x2−4x+2m≥0x^2 - 4x + 2m \geq 0 always holds. This means that the discriminant Δ=16−8m≤0\Delta = 16 - 8m \leq 0, which implies m≥2m \geq 2.

Since "m≥3m \geq 3" is a sufficient but not necessary condition for "m≥2m \geq 2", it follows that "m≥3m \geq 3" is a sufficient but not necessary condition for "proposition pp is true".

Therefore, the answer is: A\boxed{\text{A}}.

From the quadratic inequality, we have Δ=16−8m≤0\Delta = 16 - 8m \leq 0, which gives m≥2m \geq 2. Using the concept of necessary and sufficient conditions, we find that "m≥3m \geq 3" is a sufficient but not necessary condition for "m≥2m \geq 2", and thus we obtain the solution. This problem tests the understanding of quadratic inequalities and necessary and sufficient conditions, and it is considered a simple problem.

Source: NuminaMath-1.5, licensed Apache-2.0. Statement reproduced verbatim; metadata (topic, difficulty, ordering) added by this project.