Maths Olympiad Prep

Track / Stage 3 / 259 of 260 #259 of 1964

Problem 259

AMC 10/12, early questions
Number theory Difficulty 4.0 Find the answer South African Mathematics Olympiad · South Africa

The smallest number bigger than 20152015 that is divisible by all of 22, 33, 44, 55 and 66 is

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

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Official solution

20402040

In order to be divisible by 22, 33, 44, 55 and 66, the number only needs to be divisible by 22×3×52^2 \times 3 \times 5, i.e. it must be a multiple of 6060. The smallest multiple of 6060 bigger than 20152015 is 20402040.

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