We have b=a23, d=c45 from the assumption. We may assume that a=x2, c=y4 with x and y being positive integers, since a, b, c, d are all positive integers. Then a−c=x2−y4=(x−y2)(x+y2)=9. It follows that (x−y2,x+y2)=(1,9). So we obtain the solution x=5, y=2. That is, b−d=x3−y5=125−32=93.
Source: MathNet,
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