In triangle XYZ, XY=XZ and W is on XZ such that XW=WY=YZ. What is the measure of ∠XYW?
A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.
Solution
Let ∠XYW=θ. Since △XYW is isosceles with WX=WY, then ∠YXW=∠XYW=θ. Since the sum of the angles in △XYW is 180∘, then ∠XWY=180∘−2θ. Since ∠XWY+∠ZWY=180∘, then ∠ZWY=180∘−(180∘−2θ)=2θ. Since △YWZ is isosceles with YW=YZ, then ∠YZW=∠ZWY=2θ. Since △XYZ is isosceles, with XY=XZ, then ∠XYZ=∠XZY=2θ. Since the sum of the angles in △XYZ is 180∘, then ∠XYZ+∠XZY+∠YXZ=180∘ or 2θ+2θ+θ=180∘, or 5θ=180∘, or θ=36∘.
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