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Geometry Difficulty 5.2 AIME, harder Find the answer

A regular octahedron ABCDEFA B C D E F is given such that AD,BEA D, B E, and CFC F are perpendicular. Let G,HG, H, and II lie on edges AB,BCA B, B C, and CAC A respectively such that A\text{A} G}{G B = B\text{B = B} H}{H C = C\text{C = C} I}{I A=ρ.{A}=\rho. For some choice of ρ>1,GH,HI\rho>1, G H, H I, and IGI G are three edges of a regular icosahedron, eight of whose faces are inscribed in the faces of ABCDEFA B C D E F. Find ρ\rho.

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

Let JJ lie on edge CEC E such that E\text{E} J}{J C=ρ.{C}=\rho. Then we must have that HIJH I J is another face of the icosahedron, so in particular, HI=HJH I=H J. But since BCB C and CEC E are perpendicular, HJ=HC2H J=H C \sqrt{2}. By the Law of Cosines, HI2=HC2+CI22HCCIcos60=H I^{2}=H C^{2}+C I^{2}-2 H C \cdot C I \cos 60^{\circ}= HC2(1+ρ2ρ)H C^{2}\left(1+\rho^{2}-\rho\right). Therefore, 2=1+ρ2ρ2=1+\rho^{2}-\rho, or ρ2ρ1=0\rho^{2}-\rho-1=0, giving ρ=1+52\rho=\frac{1+\sqrt{5}}{2}.

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