Competition problem — Number theory

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Number theory Difficulty 4.8 AIME Find the answer

A product of five primes is of the form $A B C, A B C$ , where $A, B$ , and $C$ represent digits. If one of the primes is 491, find the product $A B C, A B C$ .

Your answer

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

$491 \cdot 1001 \cdot 2=982,982$ .

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Source: Omni-MATH, licensed Apache-2.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.