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Algebra Difficulty 4.8 AIME Find the answer

Let a0,a1,a2,a_{0}, a_{1}, a_{2}, \ldots denote the sequence of real numbers such that a0=2a_{0}=2 and an+1=an1+ana_{n+1}=\frac{a_{n}}{1+a_{n}} for n0n \geq 0. Compute a2012a_{2012}.

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

Calculating out the first few terms, note that they follow the pattern an=22n+1a_{n}=\frac{2}{2 n+1}. Plugging this back into the recursion shows that it indeed works.

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