In circle ω, two perpendicular chords intersect at a point P. The two chords have midpoints M1 and M2 respectively, such that PM1=15 and PM2=20. Line M1M2 intersects ω at points A and B, with M1 between A and M2. Compute the largest possible value of BM2−AM1.
A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.
Solution
Let O be the center of ω and let M be the midpoint of AB (so M is the foot of O to M1M2 ). Since OM1PM2 is a rectangle, we easily get that MM1=16 and MM2=9. Thus, BM2−AM1=MM1−MM2=7
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