Transforming it $k \geq 1$ times yields the diamond $\{(n, m):|n-1|+|m| \leq k+1\}$ with the points $(1, k),(1, k+1),(1,-k),(1,-k-1)$ removed (this can be seen inductively). So we get $(k+1)^{2}+k^{2}-4$ lattice points, making the answer 477.