We can take $f(x)=-\frac{2002}{d}(x-b)+2010$ for all divisors $d$ of -2002. To see that we can't get any others, note that $b-2$ must divide $f(b)-f(2)$, so $b-2$ divides -2002 (this is because $b-2$ divides $b^{n}-2^{n}$ and hence any sum of numbers of the form $b^{n}-2^{n}$).