What is the largest number of squares with side length 2 that can be arranged, without overlapping, inside a square with side length 8?
Solution
By arranging 4 rows of 4 squares of side length 2, a square of side length 8 can be formed. Thus, squares can be arranged in this way. Since these smaller squares completely cover the larger square, it is impossible to use more squares, so 16 is the largest possible number.
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