Maths Olympiad Prep

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Geometry Difficulty 4.5 AIME Prove it Soviet Union

Problem:

ABCABC is an acute-angled triangle with circumcenter OO. The circumcircle of ABOABO intersects ACAC and BCBC at MM and NN. Show that the circumradii of ABOABO and MNCMNC are the same.

Solution

Solution:

It is sufficient to show that ∠MBN=∠C\angle MBN = \angle C. But ∠MBN=∠MBO+∠OBN=∠MAO+∠OBN=∠MCO+∠OCN=∠C\angle MBN = \angle MBO + \angle OBN = \angle MAO + \angle OBN = \angle MCO + \angle OCN = \angle C.

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Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.