Maths Olympiad Prep

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, 2016

Geometry Difficulty 5.3 AIME, harder Prove it Hong Kong

Let OO be the circumcentre of a triangle ABCABC, and let ℓ\ell be the line going through the midpoint of the side BCBC and is perpendicular to the bisector of ∠BAC\angle BAC. Determine the value of ∠BAC\angle BAC if the line ℓ\ell goes through the midpoint of the line segment AOAO.

Solution

We have ∠BAC=120∘\angle BAC = 120^\circ.
Let MM be the midpoint of BCBC. Suppose ll meets the altitude from AA, the angle bisector of ∠BAC\angle BAC, and the line AOAO at EE, PP, NN respectively.
Note that AE//MOAE // MO. In order that EMEM bisects AOAO, the quadrilateral AEOMAEOM must be convex. Therefore, ∠BAC\angle BAC must be obtuse.
Now, since AE//MOAE // MO and AN=ONAN = ON, we have △AEN≅△OMN\triangle AEN \cong \triangle OMN. It is well-known that AEAE and AOAO are isogonal lines with respect to ∠BAC\angle BAC. Therefore, APAP bisects ∠EAN\angle EAN. As we also have AP⊥ENAP \perp EN, this shows △AEN\triangle AEN is isosceles, with AE=ANAE = AN. Therefore,
OM=AE=AN=12OA=12OB. OM = AE = AN = \frac{1}{2} OA = \frac{1}{2} OB.
As ∠BMO=90∘\angle BMO = 90^\circ, this yields ∠OBM=30∘\angle OBM = 30^\circ. Thus, ∠BAC=120∘\angle BAC = 120^\circ.
Figure 1

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