Maths Olympiad Prep

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Number theory Difficulty 5.3 AIME, harder Prove it Ukraine

Find all triples of positive integers a,b,ca, b, c, such that
a+[a,b]=b+[b,c]=c+[c,a], a + [a, b] = b + [b, c] = c + [c, a],
where by [x,y][x, y] we denote the smallest common multiple of x,yx, y.

Solution

Note that bb, [a,b][a, b] and [b,c][b, c] are divisible by bb, so aa is divisible by bb. Similarly, cc is divisible by aa, and bb is divisible by cc, so a=b=ca = b = c.

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Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.